Start a Function at Given Time
python, scheduler, time
Solution
Reading the docs from http://docs.python.org/py3k/library/sched.html:
Going from that we need to work out a delay (in seconds)...
from datetime import datetime
now = datetime.now()
Then use `datetime.strptime` to parse '2012-07-17 15:50:00' (I'll leave the format string to you)
# I'm just creating a datetime in 3 hours... (you'd use output from above)
from datetime import timedelta
run_at = now + timedelta(hours=3)
delay = (run_at - now).total_seconds()
You can then use `delay` to pass into a `threading.Timer` instance, eg:
threading.Timer(delay, self.update).start()
Problem
How can I run a function in Python, at a given time? For example: ``` run_it_at(func, '2012-07-17 15:50:00') ``` and it will run the function `func` at 2012-07-17 15:50:00. I tried the sched.scheduler, but it didn't start my function. ``` import time as time_module scheduler = sched.scheduler(time_module.time, time_module.sleep) t = time_module.strptime('2012-07-17 15:50:00', '%Y-%m-%d %H:%M:%S') t = time_module.mktime(t) scheduler_e = scheduler.enterabs(t, 1, self.update, ()) ``` What can I do?