Fetching only required string from the list
list, python, string
Solution
If you know that the string is litterally `"Overview:"`, you can do
''.join(list_fields[list_fields.index("Overview:") + 1:])
This uses `list.index()` to determine the index of `"Overview:"` in the list, and uses slicing to get the sublist starting at the index after `"Overview:"`.
Problem
Suppose i had list as below ``` list_fields = ['Full-Time', 'Options:', 'Express your interest', 'Email this to a friend', 'More information about this job:', 'Overview:', 'A', 'Parasite', 'position is cool', 'Are you a LEADER?', 'For sure there', 'Hello doing?', 'If so you will EXCEL.', 'Bring your skills', 'programs and procedures'] ``` what i am trying to do is collecting all the strings after `overview`, i mean need to ignore the strings before `overview` string. There may many strings before and after `overview`, but want to collect all the strings only after `overview` as a list and want to make them as a single string by using something like `''.join([list_fields])` Sorry if i am using words again and again, can anyone please tell me how to do this ``` Edited Code: ``` - Can we only fetch from after "overview:" to before 'Bring your skills'. Thanks in advance