evaluation of expression which is used with sizeof
c, expression, sizeof
Solution
Your array is not a variable-length array. A variable length array is an array whose size is not a constant expression. For example, `data` is a variable-length array in the following:
int i = 10;
char data[i];
To see an example of a code that has `sizeof` evaluate its operand, try something like this:
#include <stdio.h>
int main(void)
{
int i = 41;
printf("i: %d\n", i);
printf("array size: %zu\n", sizeof (char[i++]));
printf("i now: %d\n", i);
return 0;
}
It prints:
i: 41
array size: 41
i now: 42
Problem
Is there any expression that would be evaluated as operand of a sizeof. I have come to know in case of variable length operand with sizeof, the expression would be evaluated. But I cant make an example, I wrote the code below, ``` int a[]={1,2,3}; printf("%d",sizeof(a[1]++)); printf("%d\n",a[1]); ``` but here I observed from output expression `a[1]++` is not evaluating. how to make an example??