How to define a template member function of a template class

Possible Duplicate: How do I define a template function within a template class outside of the class definition? I'm struggling with the syntax for the case where I have a template member function within a template class: ``` template <typename T> class Foo { void Bar(const T * t); template <typename T2> void Bar(const T2 * t); }; template <typename T> void Foo<T>::Bar(const T * t) { // ... no problem ... } template <typename T> void Foo<T>::Bar<typename T2>(const T2 * t) { // ... this is where I'm tearing my hair out ... } ``` The first member function is fine, but the template member function which handles types other than the base type of the template class is where I am having problems. For the above case I get the following errors: ``` template_problem.cpp:12: error: parse error in template argument list template_problem.cpp:12: error: expected ‘,’ or ‘...’ before ‘*’ token template_problem.cpp:12: error: ISO C++ forbids declaration of ‘T2’ with no type template_problem.cpp:12: error: template-id ‘Bar<<expression error> >’ in declaration of primary template template_problem.cpp:12: error: prototype for ‘void Foo<T>::Bar(int)’ does not match any in class ‘Foo<T>’ template_problem.cpp:4: error: candidates are: template<class T> template<class T2> void Foo::Bar(const T2*) template_problem.cpp:7: error: void Foo<T>::Bar(const T*) template_problem.cpp:12: error: template definition of non-template ‘void Foo<T>::Bar(int)’ ``` and I've also tried every other syntax variation I can think of for the template version of `Bar`.