Sort hashes in array alphabetically by a field

ruby

Solution

The problem is that a and b are Hash, so you have to use "name" as the key or index instead of 0. So this should do it

@friends.sort{|a,b| a['name']<=>b['name']}

Also remember to use sort! to modify @friends variable or set it to the result

@friends.sort!{|a,b| a['name']<=>b['name']}

or

@friends = @friends.sort{|a,b| a['name']<=>b['name']}

Problem

I'd think this would be easy, and have searched for this pretty hard, but can't seem to get it to work. I have the following hash: ``` @friends = [{"name"=>"John Smith", "id"=>"12345"}, {"name"=>"Jane Doe", "id"=>"23456"}, {"name"=>"Samuel Jackson", "id"=>"34567"}, {"name"=>"Kate Upton", "id"=>"45678"}] ``` I'm trying to sort it alphabetically by the name. Right now I"m doing this: ``` @friends.sort{|a,b| a[0]<=>b[0]} ``` However, it just outputs the full results in non-alphabetical order.

Original source