split apply recombine, plyr, data.table in R
apply, data.table, plyr, r, split
Solution
I'm guessing this needs to be sorted by "id" to line up properly. Luckily that happens automatically when you set the key:
dat <-read.table(text="dte, id, val1, val2
2001-10-02, 1, 10, 25
2001-10-03, 1, 11, 24
2001-10-04, 1, 12, 23
2001-10-02, 2, 13, 22
2001-10-03, 2, 14, 21
", header=TRUE, sep=",")
dtb <- data.table(dat)
setkey(dtb, "id")
dtb[, residuals(lm(val1 ~ val2)), by="id"]
#---------------
cbind(dtb, dtb[, residuals(lm(val1 ~ val2)), by="id"])
#---------------
dte id val1 val2 id.1 V1
[1,] 2001-10-02 1 10 25 1 1.631688e-15
[2,] 2001-10-03 1 11 24 1 -3.263376e-15
[3,] 2001-10-04 1 12 23 1 1.631688e-15
[4,] 2001-10-02 2 13 22 2 0.000000e+00
[5,] 2001-10-03 2 14 21 2 0.000000e+00
> dat <- data.frame(dte=Sys.Date()+1:1000000,
id=sample(1:2, 1000000, repl=TRUE),
val1=runif(1000000), val2=runif(1000000) )
> dtb <- data.table(dat)
> setkey(dtb, "id")
> system.time( cbind(dtb, dtb[, residuals(lm(val1 ~ val2)), by="id"]) )
user system elapsed
1.696 0.798 2.466
> system.time( dtb[,transform(.SD,r = residuals(lm(val1~val2))),by = "id"] )
user system elapsed
1.757 0.908 2.690
EDIT from Matthew : This is all correct for v1.8.0 on CRAN. With the small addition that `transform` in `j` is the subject of data.table wiki point 2: "For speed don't `transform()` by group, `cbind()` afterwards". But, `:=` now works by group in v1.8.1 and is both simple and fast. See my answer for illustration (but no need to vote for it).
Well, I voted for it. Here is the console command to install v 1.8.1on a Mac (if you have the proper XCode tools avaialble, since it only there in source):
install.packages("data.table", repos= "http://R-Forge.R-project.org", type="source",
lib="/Library/Frameworks/R.framework/Versions/2.14/Resources/lib")
(For some reason I could not get the Mac GUI Package Installer to read r-forge as a repository.)
Problem
I am doing the classic split-apply-recombine thing in R. My data set is a bunch of firms over time. The applying I am doing is running a regression for each firm and returning the residuals, therefore, I am not aggregating by firm. `plyr` is great for this but it takes a very very long time to run when the number of firms is large. Is there a way to do this with `data.table`? Sample Data: ``` dte, id, val1, val2 2001-10-02, 1, 10, 25 2001-10-03, 1, 11, 24 2001-10-04, 1, 12, 23 2001-10-02, 2, 13, 22 2001-10-03, 2, 14, 21 ``` I need to split by each id (namely 1 and 2). Run a regression, return the residuals and append it as a column to my data. Is there a way to do this using `data.table`?