Linux shell script for delete old files from ftp
ftp, shell
Solution
This is a script I wrote to remove any files on a remote ftp site older than 7 days. It works by retrieving a listing of the directory, parsing the modified date, and then re-connecting to delete any files older than ndays.
I suspect that the numbers hard-coded into the loop (element date) may change depending on the setup of your system. The return formatting of the ls command is dependent on the local system settings.
Assuming your backups are every day, then setting ndays to 10 might solve your problem.
#!/bin/bash
# get a list of files and dates from ftp and remove files older than ndays
ftpsite="ftp.yourserver.com"
ftpuser="loginusername"
ftppass="password"
putdir="/public_ftp/admin/logs"
ndays=7
# work out our cutoff date
MM=`date --date="$ndays days ago" +%b`
DD=`date --date="$ndays days ago" +%d`
echo removing files older than $MM $DD
# get directory listing from remote source
listing=`ftp -i -n $ftpsite <<EOMYF
user $ftpuser $ftppass
binary
cd $putdir
ls
quit
EOMYF
`
lista=( $listing )
# loop over our files
for ((FNO=0; FNO<${#lista[@]}; FNO+=9));do
# month (element 5), day (element 6) and filename (element 8)
#echo Date ${lista[`expr $FNO+5`]} ${lista[`expr $FNO+6`]} File: ${lista[`expr $FNO+8`]}
# check the date stamp
if [ ${lista[`expr $FNO+5`]}=$MM ];
then
if [[ ${lista[`expr $FNO+6`]} -lt $DD ]];
then
# Remove this file
echo "Removing ${lista[`expr $FNO+8`]}"
ftp -i -n $ftpsite <<EOMYF2
user $ftpuser $ftppass
binary
cd $putdir
delete ${lista[`expr $FNO+8`]}
quit
EOMYF2
fi
fi
done
Problem
There is a problem - need to store the database backup on the FTP. On the FTP should not be more than 10 back-ups, ie, After you add backup to FTP should be removed, the oldest files to make the total number of files can not exceed 10 pieces. How can we implement such a removal from the ftp? I'm trying to write a script, but does not work delete: ``` x=1 ftp -vn $FTP_SERVER<<! user $FTP_LOGIN $FTP_PASSWORD binary put $DUMP_FILE_NAME for i in `ls -t` do if [ $x -le $keep ] then ((x++)) continue fi delete $i done bye EOF </i> ```