Redirect lsof exit code into variable

bash, linux, lsof

Solution

Well, you could do:

lsof "$FILE" | grep -q COMMAND; completed=$?

There's no need to redirect anything as grep -q is quiet anyways. If you want do certain action if the grep succeeds, just use && operator. Storing exit status in this case is probably unnecessary.

lsof "$FILE" | grep -q COMMAND && echo 'Command was found!'

Problem

I'm trying to test whether a file is open and then do something with the exit code. Currently doing it like this: ``` FILE=/usr/local/test.sh lsof "$FILE" | grep -q COMMAND &>/dev/null completed=$? ``` Is there any way you can push the exit code straight into a local variable rather than redirecting output to /dev/null and capturing the '$?' variable?

Original source