How to convert this c code to c++ in opencv

opencv

Solution

Refer to:

- http://opencv.willowgarage.com/documentation/cpp/c++_cheatsheet.html

- and http://opencv.willowgarage.com/wiki/Welcome?action=AttachFile&do=get&target=opencv_cheatsheet.pdf

For example,

IplImage *imgY = cvCreateImage(imageSize, IPL_DEPTH_8U, 1);

becomes

cv::Mat imgY = cv::Mat(imageSize, CV_8UC1);

and

cvCvtColor(img,imgYCrCb,CV_BGR2YCrCb);

becomes

cv::cvtColor(img, imgYCrCb, CV_BGR2YCrCb);

and so on ...

Edit :

Answer to your comment : OpenCV 2 removes the need to manage manually the memory.

So, the code can be rewritten as :

cv::Mat imgYCrCb;
std::vector<cv::mat> yCrCb_channels;

cv::cvtColor(img,imgYCrCb,CV_BGR2YCrCb);   
cv::split(imgYCrCb, yCrCb_channels);
unsigned char * pY = (uchar *) yCrCn_channels[1].data;

Advice : read http://www.amazon.com/dp/1849513244/?tag=stackoverfl08-20 , it covers the C++ opencv interface.

Problem

I'm a starter in opencv, and Learning Opencv has is code written in C. I need to convert to C++. ``` IplImage *imgY = cvCreateImage(imageSize, IPL_DEPTH_8U, 1); IplImage *imgCr = cvCreateImage(imageSize, IPL_DEPTH_8U, 1); IplImage *imgCb = cvCreateImage(imageSize, IPL_DEPTH_8U, 1); IplImage *imgYCrCb = cvCreateImage(imageSize, img->depth, img->nChannels); cvCvtColor(img,imgYCrCb,CV_BGR2YCrCb); cvSplit(imgYCrCb, imgY, imgCr, imgCb, 0); unsigned char *pY, *pCr, *pCb, *pMask; pY = (unsigned char *)imgY->imageData; pCr = (unsigned char *)imgCr->imageData; pCb = (unsigned char *)imgCb->imageData; pMask = (unsigned char *)mask->imageData; ```

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