How to select these elements with Xpath?

xpath, xslt

Solution

Short answer (assuming current() is ok, since this is tagged xslt):

following-sibling::B[preceding-sibling::A[1]/@node = current()/@node]

Example stylesheet:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml"/>
    <xsl:template match="/">
        <xsl:apply-templates select="/root/A"/>
    </xsl:template>

    <xsl:template match="A">
        <div>A: <xsl:value-of select="@node"/></div>
        <xsl:apply-templates select="following-sibling::B[preceding-sibling::A[1]/@node = current()/@node]"/>
    </xsl:template>

    <xsl:template match="B">
        <div>B: <xsl:value-of select="@node"/></div>
    </xsl:template>
</xsl:stylesheet>

Good luck!

Problem

I have a document, something like this: ``` <root> <A node="1"/> <B node="2"/> <A node="3"/> <A node="4"/> <B node="5"/> <B node="6"/> <A node="7"/> <A node="8"/> <B node="9"/> </root> ``` Using xpath, How can I select all B elements that consecutively follow a given A element? It's something like following-silbing::B, except I want them to be only the immediately following elements. If I am on A (node==1), then I want to select node 2. If I am on A (node==3), then I want to select nothing. If I am on A (node==4), then I want to select 5 and 6. Can I do this in xpath? EDIT: It is within an XSL stylesheet select statement. EDIT2: I don't want to use the node attribute on the various elements as a unique identifier. I included the node attribute only for purposes of illustrating my point. In the actual XML doc, I don't have an attribute that I use as a unique identifer. The xpath "following-sibling::UL[preceding-sibling::LI[1]/@node = current()/@node]" keys on the node attribute, and that's not what I want.

Original source