How do I output a drupal image field?
drupal, drupal-7, drupal-themes, drupal-theming
Solution
You are looking for `image_style_url(style_name, image_url);`
For example:
<?='<img src="'.image_style_url('fullwidth', $node->field_page_image['und'][0]['filename']).'" />'?>
EDIT
As pointed out you can also set the image style in the Manage Display page for the content type and then output using render.
<?php print render($content['field_image']); ?>
Problem
It is quite possible that I'm just looking for help finding the name of a function that already exists within drupal (7) but sometimes the documentation is a bit difficult to navigate. Hopefully someone can help me. I have a node that has a custom field. I am working within a template `field--mycustomcontenttype.tpl.php` and so am trying to find the name of the PHP function that outputs and image field with image styles. `mycustomcontenttype` is a NODE with the following additional field: ``` [field_image] => Array ( [und] => Array ( [0] => Array ( [fid] => 51 [alt] => ImageAltText [title] => [width] => 150 [height] => 150 [uid] => 29 [filename] => myimagename.jpg [uri] => public://myimagename.jpg [filemime] => image/jpeg [filesize] => 8812 [status] => 1 [timestamp] => 1339445372 [uuid] => a088ea8f-ddf9-47d1-b013-19c8f8cada07 [metatags] => Array ( ) ) ``` So I could display the image using an (ugly) hand rolled functions that takes the value found in `$item['#options']['entity']->field_image` and does the substitution of `public://` for the actual server path, and then it's also possible that I'm going to want to load the image with the correct drupal image style (thumbnail, custom-style, etc...) Sadly, I just have no idea what the name of the function that works something like: `unknown_function_name_drupal_image_print($item['#options']['entity']->field_image, 'thumnail');` is. Is there anyone who can help me find this?