Directory Name + File Name to Text File

Question

I have many directories with files in them. I want to create a comma delimited txt file showing directory name, and the files that are within that particular directory, see example below: What I'm looking for: ``` DirName,Filename 999,123.tif 999,1234.tif 999,abc.tif 900,1236.tif 900,xyz.tif ...etc ``` The python code below pushes a list of those file paths into a text file, however I'm unsure of how to format the list as described above. My current code looks like: Update I've been able to format the text file now, however I'm noticing all the directory names/filenames are not being written to the text file. It is only writing ~4000 of the ~8000 dir/files. Is there some sort limit that I'm reaching with the text file number of rows, the list (mylist) size, or some bad file dir/file character that is stopping it (see updated code below)? ``` from os import listdir from os.path import isfile, join root = r'C:	emp' mylist = ['2'] for path, subdirs, files in os.walk(root): for name in f…

Accepted Answer

Maybe this helps:

You could get the absolute file paths and then do the following

```
import os.path
p = "/tmp/999/123.tif"
dir, filename = os.path.basename(os.path.dirname(p)), os.path.basename(p)
```

Result:

```
In [21]: dir
Out[21]: '999'

In [22]: filename
Out[22]: '123.tif'
```

Also consider using csv module to write this kind of files.

```
import csv
import os.path

# You already have a list of absolute paths
files = ["/tmp/999/123.tif"]

# csv writer
with open('/tmp/out.csv', 'wb') as out_file:
    csv_writer = csv.writer(out_file, delimiter=',')
    csv_writer.writerow(('DirName','Filename'))
    for f in files:
        csv_writer.writerow((os.path.basename(os.path.dirname(f)), 
                             os.path.basename(f)))
```

Directory Name + File Name to Text File

Solution

Problem