DWORD64 if set to -1 gives 32 1s i.e. 0xffffffffffffffffffffffffffffffff
c++, dword
Solution
You problem here lies in the `printf` format string. Using `%u` tells `printf` to print a 32 bits value. Hence, it uses only the first 32 bits of your `DWORD64`. To print all the 64 bits that has been pushed onto the stack, use `%llu` (for `unsigned long long`).
Note also that `DWORD64` cannot be `unsigned long`. On all Windows versions, even on Windows 64 bits, `long` is 32 bits.
See LLP64 model.
Problem
C++ code (Visual studio started with devenv /useenv (x64) and isWOW64 is false) ``` DWORD64 check; check = -1; printf("value %u", check); ``` it prints the value 4294967295 i.e. 0x(32)f which is the same if i do it with simple DWORD in an x32 environment yes i know DWORD64 is unsigned __int64, but shouldn't it be 0x(64)f ? what did the assembler do there ? disassembling the code didn't help me much.