Generating all distinct permutations of a list in R
permutation, r
Solution
`combinat::permn` will do that work:
> library(combinat)
> permn(letters[1:3])
[[1]]
[1] "a" "b" "c"
[[2]]
[1] "a" "c" "b"
[[3]]
[1] "c" "a" "b"
[[4]]
[1] "c" "b" "a"
[[5]]
[1] "b" "c" "a"
[[6]]
[1] "b" "a" "c"
Note that calculation is huge if the element is large.
Problem
I'm trying to create a list of permutations of a list, such that, for example, `perms(list("a", "b", "c"))` returns ``` list(list("a", "b", "c"), list("a", "c", "b"), list("b", "a", "c"), list("b", "c", "a"), list("c", "a", "b"), list("c", "b", "a")) ``` I'm not sure how to proceed, any help would be greatly appreciated.