Choice and Errorlevel?

batch-file

Solution

The `if errorlevel` expression evaluates to true if actual error level returned by choice is greater or equal to given value. So if you hit 3, the first if expression is true and script terminates. Call `help if` for more information.

There are two simple workarounds.

First one (better) - replace `if errorlevel` expression with actual comparision of `%ERRORLEVEL%` system variable with a given value:

if "%ERRORLEVEL%" == "1" goto exit
if "%ERRORLEVEL%" == "2" goto about
if "%ERRORLEVEL%" == "3" goto play

Second one - change order of comparisions:

if errorlevel 3 goto play
if errorlevel 2 goto about
if errorlevel 1 goto exit

Problem

I do something like this: ``` echo 1-exit echo 2-about echo 3-play choice /c 123 >nul if errorlevel 1 goto exit if errorlevel 2 goto about if errorlevel 3 goto play :play blah :about blah :exit cls ``` If I select the "play" option, it exits. How do I prevent this from happening?

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