open() function python default directory
python
Solution
`os.getcwd()`
Shows the current working directory, that's what `open` uses for for relative paths. You can change it with `os.chdir`.
Problem
I'm new and I have no idea where the default directory for the `open()` function is. For example `open('whereisthisdirectory.txt','r')` Can someone advise me? I've tried googling it (and looking on stackoverflow) and even putting a random txt file in so many folders but I still can't figure it out. Since I'm beginning, I want to learn immediately rather than type "c:/directory/whatevevr.txt" every time I want to open a file. Thanks! Ps my python directory has been installed to C:\Python32 and I'm using 3.2