Pass two variable argument list

python

Solution

This is not possible because `*arg` captures all positional args from that position on. So by definition, a second `*args2` would always be empty.

An easy solution would be passing two tuples:

def myfunction(type, id, args1, args2):
    other_function(args1)
    other_function2(args2)

and call it like this:

myfunction(type, id, (1,2,3), (4,5,6))

In case the two functions expect positional arguments instead of a single argument, you would call them like this:

def myfunction(type, id, args1, args2):
    other_function(*arg1)
    other_function2(*arg2)

This would have the advantage that you can use any iterable, even a generator, when calling `myfunction` since the called functions would never get in contact with the passed iterables.

If you really want to work with two variable argument lists you need some kind of separator. The following code uses `None` as the separator:

import itertools
def myfunction(type, id, *args):
    args = iter(args)
    args1 = itertools.takeuntil(lambda x: x is not None, args)
    args2 = itertools.dropwhile(lambda x: x is None, args)
    other_function(args1)
    other_function2(args2)

It would be used like this:

myfunction(type, id, 1,2,3, None, 4,5,6)

Problem

I know this works very well: ``` def locations(city, *other_cities): print(city, other_cities) ``` Now I need two variable argument list, like ``` def myfunction(type, id, *arg1, *arg2): # do somethong other_function(arg1) #do something other_function2(*arg2) ``` But Python does not allow to use this twice

Original source