Ternary comparison operator overloading

c++, operator-overloading

Solution

Solution: When coding a comparison, have the return type be a `comparison` object that can chain additional comparisons, but is implicitly convertible to a `bool`. This can even (kind of) work with types that weren't coded with this intent, simply by casting them to the `comparison` type manually.

Implementation:

template<class T>
class comparison {
  const bool result;
  const T& last;
public:
  comparison(const T& l, bool r=true) :result(r), last(l) {}
  operator bool() const {return result;}
  comparison operator<(const T& rhs) const {return comparison(rhs, (result && last<rhs));}
  comparison operator<=(const T& rhs) const {return comparison(rhs, (result && last<=rhs));}
  comparison operator>(const T& rhs) const {return comparison(rhs, (result && last>rhs));}
  comparison operator>=(const T& rhs) const {return comparison(rhs, (result && last>=rhs));}
};

A useful example:

#include <iostream>
int main() {
  //testing of chained comparisons with int
  std::cout << (comparison<int>(0) < 1 < 2) << '\n';
  std::cout << (comparison<int>(0) < 1 > 2) << '\n';
  std::cout << (comparison<int>(0) > 1 < 2) << '\n';
  std::cout << (comparison<int>(0) > 1 > 2) << '\n';
}

Output:

1
0
0
0

Note: This was created by Mooing Duck, and a compiled, more robust example can be found on http://ideone.com/awrmK

Problem

Original source