Conditional test around xsl:apply-templates

I've been trying to learn how to code in xslt and currently am stuck on how to use conditional tests around the xsl:apply-templates tag. Here's the xml that I am testing. ``` <?xml version="1.0" encoding="utf-8"?> <catalog> <cd> <title>Empire Burlesque</title> <artist>Bob Dylan</artist> <country>USA</country> <company>Columbia</company> <price>10.90</price> <year>1985</year> </cd> <cd> <title>Hide your heart</title> <artist>Bonnie Tyler</artist> <country>UK</country> <company>CBS Records</company> <price>9.90</price> <year>1988</year> </cd> <cd> <title>Greatest Hits</title> <artist>Dolly Parton</artist> <country>USA</country> <company>RCA</company> <price>9.90</price> <year>1982</year> </cd> ``` Here is my xslt ``` <xsl:template match="/"> <xsl:apply-templates select="catalog/cd" /> </xsl:template> <xsl:template match="cd"> <p> <xsl:apply-templates select="artist" /> <br /> <xsl:apply-templates select="country" /> <br /> <xsl:if test="country != 'USA' and year != '1985'"> <xsl:apply-templates select="year" /> </xsl:if> </p> </xsl:template> <xsl:template match="artist"> <xsl:value-of select="." /> </xsl:template> <xsl:template match="country"> <xsl:value-of select="." /> </xsl:template> <xsl:template match="year"> <xsl:value-of select="." /> </xsl:template> ``` Here is my output: ``` Bob Dylan USA Bonnie Tyler UK 1988 Dolly Parton USA ``` Here is the output I was expecting: ``` Bob Dylan USA Bonnie Tyler UK 1988 Dolly Parton USA 1982 ``` Even though I want to remove the year only when country has a value of USA and year has a value of 1985 it is removing the year every time country has a value of USA only. Is there a better way I can use apply-templates?