Difference between int and int received by ParseInt in java

java, parseint

Solution

Use brackets as follows

System.out.println((i+1) + " " + (j+1));

From the docs

The + operator is syntactically left-associative, no matter whether it is later determined by type analysis to represent string concatenation or addition. In some cases care is required to get the desired result. For example, the expression:

a + b + c is always regarded as meaning: (a + b) + c

Extending this to your scenario

i+1 + " " + j+1

it becomes

(((i + 1) + " ") + j)+1

Since `i` is an int so `(i + 1) = 1` , simple addition

`" "` is a `String` hence `((i + 1) + " ")` = `1` WITH SPACE (String concatenation)

Similarly when `j` and last `1` is added, its being added to a `String` hence `String` concatenation takes place, which justifies the output that you are getting.

See

- JLS 15.18.1 String Concatenation Operator +

Problem

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