how to get 10th grouping value in sed?
sed, unix
Solution
`sed` only supports 10 groups(from `\0` to `\9`), and doesn't support non-captured group.
You can rewrite you command as:
sed 's/[a-z][A-Z][0-9][a-z][A-Z][0-9][a-z][A-Z][0-9]\([a-z]\)/\1/g'
Problem
It is my sed. ``` sed 's/\([a-z]\)\([A-Z]\)\([0-9]\)\([a-z]\)\([A-Z]\)\([0-9]\)\([a-z]\)\([A-Z]\)\([0-9]\)\([a-z]\)/\10/g' ``` I tried to get 10th grouping value.But,It gives first grouping value with 0(zero). How to get 10th grouping value? whether it is possible to get the 10th grouping value?