Regex filter numbers divisible by 3
python, regex
Solution
If you really mean digits (not numbers), this is as easy as
re.findall(r'[369]', my_str)
For a list of numbers, it's quite easy without regular expressions:
lst = "55,62,12,72,55"
print [x for x in lst.split(',') if int(x) % 3 == 0]
Problem
I have a list of comma-separated ids(digits) . And I need to get only these which are divisible by 3. `Example: i = "3454353, 4354353, 345352, 2343242, 2343242 ..."`