The result list contains single spaces when splitting a string with re.split("( )+") – is there a better way?
python, python-re, split
Solution
By using `(`,`)`, you are capturing the group, if you simply remove them you will not have this problem.
>>> str1 = "a b c d"
>>> re.split(" +", str1)
['a', 'b', 'c', 'd']
However there is no need for regex, `str.split` without any delimiter specified will split this by whitespace for you. This would be the best way in this case.
>>> str1.split()
['a', 'b', 'c', 'd']
If you really wanted regex you can use this (`'\s'` represents whitespace and it's clearer):
>>> re.split("\s+", str1)
['a', 'b', 'c', 'd']
or you can find all non-whitespace characters
>>> re.findall(r'\S+',str1)
['a', 'b', 'c', 'd']
Problem
I have the output of a command in tabular form. I'm parsing this output from a result file and storing it in a string. Each element in one row is separated by one or more whitespace characters, thus I'm using regular expressions to match 1 or more spaces and split it. However, a space is being inserted between every element: ``` >>> str1 = "a b c d" # spaces are irregular >>> str1 'a b c d' >>> str2 = re.split("( )+", str1) >>> str2 ['a', ' ', 'b', ' ', 'c', ' ', 'd'] # 1 space element between! ``` Is there a better way to do this? After each split `str2` is appended to a list.