Opposite of Bitwise OR operation
bit-manipulation, bitwise-operators, language-agnostic
Solution
This is impossible.
A simple case to demonstrate my point (assuming a, b, and c are all 1-bit):
If 'b' is 1, 'c' will always be 1, you cannot determine the value of 'a'.
Problem
I compute ``` c = a 'OR' b // bitwise OR operation here ``` Now given only values of `c` and `b` how can I compute the original value of `a`?