How to print out each bytes' contents in a 4-byte int
byte, c++, endianness, linux
Solution
the issue is that the type of `*p` is `char`, so the stream attempts to print the value of it as an ASCII character (which is likely not the value of a visible character). If you cast it to an `int` you will get what you expect:
cout << "p[" << i << "] is " << hex << static_cast<int>(*p++) << " ";
Problem
I designed a C++ code for checking machine's endian. It works well. But, it cannot print out each bytes' contents in a 4-byte int. ``` #include<iostream> using namespace std; bool f() { int a = 1; char *p = (char*)&a; for (int i = 0 ; i < 4 ; ++i) cout << "p[" << i << "] is " << hex << *p++ << " "; cout << endl ; p -= 4; if (*p == 1) return true ; // it is little endian else return false; // it is big endian } int main() { cout << "it is little endian ? " << f() << endl ; return 0 ; } ``` output: ``` p[0] is p[1] is p[2] is p[3] is it is little endian ? 1 ``` Why the output is empty ? thanks