Adding const keyword to an array passed as a parameter to function
c, pointers
Solution
In C you have to put `const` between the `[]`, however strange that might look to an unprepared person
void foo(char arr_arg[const]);
This is "new" C99-specific syntax. In C89/90 or C++ there no way to do it with "array" syntax, so you have to switch to the equivalent "pointer" syntax, as suggested in David's answer.
Problem
Is there any way that I can add `const` keyword to an array passed as a parameter to function: ``` void foo(char arr_arg[]) ``` If I place `const` before `char` (`void foo(const char arr_arg[])`) or after `char`(`void foo(char const arr_arg[])`), that would mean than it's `char` which is constant, not the `arr_arg`. I have just read that under the hood an array sent as a parameter to function is represented as a pointer, so `void foo(char arr_arg[])` is the same as `void foo(char* ptr_arg)`. Taking it into account, I may rewrite the function as `void foo(char * const ptr_arg)` for it to be exactly what I want to achieve. But I want to know if there is a way to add `const` keyword in this declaration `void foo(char arr_arg[])` for it to be the same as `void foo(char * const ptr_arg)` (and not `void foo(char const * ptr_arg)` or `void foo(const char * ptr_arg)`)? I just want to understand if there is a syntax to make `arr_arg` constant with array notation `[]`.