Extracting a zipfile to memory?
memory, python, python-zipfile, stringio, zip
Solution
`extractall` extracts to the file system, so you won't get what you want. To extract a file in memory, use the `ZipFile.read()` method.
If you really need the full content in memory, you could do something like:
def extract_zip(input_zip):
input_zip=ZipFile(input_zip)
return {name: input_zip.read(name) for name in input_zip.namelist()}
Problem
How do I extract a zip to memory? My attempt (returning `None` on `.getvalue()`): ``` from zipfile import ZipFile from StringIO import StringIO def extract_zip(input_zip): return StringIO(ZipFile(input_zip).extractall()) ```