How to delete a key and return the value from a PHP array?

arrays, php

Solution

I don't see a built-in function for this, but you can easily create your own.

/**
 * Removes an item from the array and returns its value.
 *
 * @param array $arr The input array
 * @param $key The key pointing to the desired value
 * @return The value mapped to $key or null if none
 */
function array_remove(array &$arr, $key) {
    if (array_key_exists($key, $arr)) {
        $val = $arr[$key];
        unset($arr[$key]);

        return $val;
    }

    return null;
}

You can use it with any array, e.g. `$_SESSION`:

return array_remove($_SESSION, 'AFTER_LOGIN_TARGET');

Short and Sweet

With PHP 7+ you can use the null coalescing operator to shorten this function greatly. You don't even need `isset()`!

function array_remove(array &$arr, $key) {
    $val = $arr[$key] ?? null;
    unset($arr[$key]);
    return $val;
}

Problem

When using PHP, I find myself writing code like this a lot: ``` $target = $_SESSION[AFTER_LOGIN_TARGET]; unset($_SESSION[AFTER_LOGIN_TARGET]); return $target; ``` In Python, there is a `dict.pop` method that would let me do something similar in one statement, without a temporary variable: ``` return session.pop(AFTER_LOGIN_TARGET) ``` Is there a similar function or trick in PHP?

Original source

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