Python list of tuples
python
Solution
`[(k, dict(L2).get(k, '')) for k in L1]`
You can pull the `dict(L2)` out of the list comprehension if you don't want to recalculate it each time (e.g., if L2 is large).
d = dict(L2)
[(k, d.get(k, '')) for k in L1]
Problem
``` L1 = ['A', 'B', 'C', 'D'] L2 = [('A', 10)], ('B', 20)] ``` Now from these two list how can i generate common elements ``` output_list = [('A', 10), ('B', 20), ('C', ''), ('D', '')] ``` How can i get output_list using L1 and L2? I tried the following ``` for i in L2: for j in L1: if i[0] == j: ouput_list.append(i) else: output_list.append((j, '')) ``` But i'm not getting the exact out which i want