C/C++ va_list not returning arguments properly
c, c++, variadic-functions
Solution
In the context of a varargs call, `float` is actually promoted to `double`. Thus, you'll need to actually be pulling `double`s out, not `float`s. This is the same reason that `%f` for `printf()` works with both `float` and `double`.
Problem
I have a problem with using va_list. The below code works for an int: ``` main() { int f1=1; float** m = function(n,f1); } float** function(int n,...) { va_list mem_list; va_start(mem_list, n); for (int i=0;i<n;i++) { for (int j=0;j<n;j++) { //m[i][j]=va_arg(mem_list,float); int f = va_arg(mem_list,int); printf("%i \n",f); } } va_end(mem_list); return NULL; } ``` However when I change to a float i.e. ``` float f1=1.0; float f = va_arg(mem_list,float); printf("%f \n",f); ``` It does not return the right value (the value is 0.00000). I am extremely confused at what is happening.