How does Serializable work?
java, serializable
Solution
I think the behavior you're looking for would be better implemented using annotations and the annotation processor. The fact that the compiler warns you about not declaring `serialVersionUID` is handled by a different mechanism at the compiler level (and therefore, out of the reach of the programmer); it's more of a coding convention enforced by the serialization API than a consequence of implementing the `Serializable` interface.
In fact, here you can examine the source code of `Serializable` and as you can see, there's nothing special about it for forcing a compiler warning:
/* comments removed for brevity */
package java.io;
public interface Serializable {
}
Problem
This question is not about how to use `Serializable`, I already know that. However, I was wondering how implementing `Serializable` brings up the following warning: `The serializable class MyClass does not declare a static final serialVersionUID field of type long` Suppose I wanted to write an interface like `Serializable`, how would I go about "warning" the programmer implementing my interface to declare a variable? I've tried looking at the source code for `Serializable.java` but I couldn't find anything which would result in this behaviour. Is this even possible? Thanks!