How to include file in a bash shell script
bash, include, linux
Solution
Simply put inside your script :
source FILE
Or
. FILE # POSIX compliant
$ LANG=C help source
source: source filename [arguments]
Execute commands from a file in the current shell.
Read and execute commands from FILENAME in the current shell. The
entries in $PATH are used to find the directory containing FILENAME.
If any ARGUMENTS are supplied, they become the positional parameters
when FILENAME is executed.
Exit Status:
Returns the status of the last command executed in FILENAME; fails if
FILENAME cannot be read.
Problem
Is there a way to include another shell script in a shell script to be able to access its functions? Like how in PHP you can use the `include` directive with other PHP files in order to run the functions that are contained within simply by calling the function name.