4-dimensional array allocation: access violation

I wrote this simple piece of code to dynamically allocate a 4-dimensional array: ``` #include <stdlib.h> #include <stdio.h> int**** alloc() { int i,j,k; int ****matrix; int x,y,z,n_pairs; x= 62; y= 45; z= 28; n_pairs = 4; matrix = (int ****) malloc(x*sizeof(int***)); for (i=0; i<x; i++) { matrix[i] = (int ***) malloc(y*sizeof(int**)); if(matrix[i]==NULL) return NULL; for (j=0; j<y; j++) { matrix[i][j] = (int **) malloc(z*sizeof(int*)); if (matrix[i][j] == NULL) return NULL; for (k=0; k<n_pairs; k++) { matrix[i][j][k] = (int *)calloc(n_pairs,sizeof(int)); if (matrix[i][j][k] == NULL) return NULL; } } } return matrix; } void freeMatrix(int ****m) { int i,j,k; int x,y,z; x= 62; y= 45; z= 28; for(i=0; i<x; i++) { for(j=0; j<y; j++) { for(k=0; k<z; k++) free(m[i][j][k]); free(m[i][j]); } free(m[i]); } free(m); } int main() { int i,j,k,h; int ****m = NULL; m = alloc(); for(i=0;i<62;i++) for(j=0;j<45;j++) for(k=0;k<28;k++) for(h=0;h<4;h++) printf("%d\t",m[i][j][k][h]); system("pause"); return 0; } ``` the problem is that I this code results in an `Access Violation` when I try to execute it. Isn't it the correct way to allocate/free a multidimensional array? If yes, then what is the problem?