Best way to print list output in python

list, python

Solution

Well, you could avoid some temporary variables and use a nicer loop:

for label, vals in zip(list1, list2):
    print label
    print '---'.join(vals)

I don't think you're going to get anything fundamentally "better," though.

Problem

I have a `list` and a `list of list` like this ``` >>> list2 = [["1","2","3","4"],["5","6","7","8"],["9","10","11","12"]] >>> list1 = ["a","b","c"] ``` I zipped the above two list so that i can match their value index by index. ``` >>> mylist = zip(list1,list2) >>> mylist [('a', ['1', '2', '3', '4']), ('b', ['5', '6', '7', '8']), ('c', ['9', '10', '11', '12'])] ``` Now I tried to print the output of above `mylist` using ``` >>> for item in mylist: ... print item[0] ... print "---".join(item[1]) ... ``` It resulted in this output which is my `desired output`. ``` a 1---2---3---4 b 5---6---7---8 c 9---10---11---12 ``` Now, my question is there a more `cleaner and better` way to achieve my desired output or this is the `best(short and more readable)` possible way.

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