Two C syntax tidbits: no init for and char *w[4] vs char w[4]
c, syntax
Solution
It's been a while, but here should be the differences:
for ( ; *p == *q; p++, q++)
This is simply that the developer doesnt want to do any initialization prior to the for loop. In this case the developer simply wants to iterate through the pointers.
char *word[800000];
and
char word[800000];
The first declares an array of 800000 char*, the second is an array of 800000 chars
Hope that helps
Problem
Just studying the C style of Jon Bentley's Programming Pearls and was wondering if someone could please explain to me the following two pieces of C syntax: A `for` with no init condition (see line 2 in wordncmp in the file above): ``` for ( ; *p == *q; p++, q++) ``` and the semantic difference between ``` char *word[800000]; ``` and ``` char word[800000]; ``` since I thought arrays were just pointers to, in this case, `word[0]`. Answer choice explanation: Ok, as the rest of the community, I was torn between accepting dmckee or CAbbott answer. They both have important pieces of knowledge that I appreciate. I've accepted CAbbott answer because it was simpler, but gave an upvote to dmckee. As fair as I could go without accepting two answers. Thanks.