how do I check that two slices of numpy arrays are the same (or overlapping)?
numpy, python
Solution
`numpy.may_share_memory()` is the best heuristic that we have at the moment. It is conservatively heuristic; it may give you false positives, but it will not give you false negatives. I think there might be ways to improve the heuristic to be 100% correct. If they pan out, they will be folded into that function, so that's the best way forward.
Problem
I would like to check if two ndarrays are overlapping views of the same underlying ndarray. To check that two slices are exactly the same, I can do something like: ``` a.base is b.base and a.shape == b.shape and a.data == b.data ``` The comparison of buffers seemed to work in one simple case -- can anyone tell me if it works in general? Unfortunately, this wont work for overlapping slices, and I haven't figured out how to extract from the buffer exactly what its offset is in the underlying data -- perhaps someone can help me with this? Also, say `a` and `b` are slices of `x`, and `c` is a slice of `b`. As the underlying data is the same, I would also like to detect overlaps between `c` and `a`. It would seem that I should be able to get away with comparing just buffer and shape... if anyone could tell me exactly how, I would be grateful.