split on last occurrence of digit, take 2nd part
r, regex
Solution
library(stringr)
unlist(lapply(str_split(x, "[0-9]"), tail,n=1))
gives
[1] "ID" "Alabama" "Alaska" "Arizona" "Arkansas" "California" "Colorado" "Connecticut" "Delaware"
[10] "Florida" "Georgia"
I would look at the documentation `stringr` for (most possibly) an even better approach.
Problem
If I have a string and want to split on the last digit and keep the last part of the split hpw can I do that? ``` x <- c("ID", paste0("X", 1:10, state.name[1:10])) ``` I'd like ``` [1] NA "Alabama" "Alaska" "Arizona" "Arkansas" [6] "California" "Colorado" "Connecticut" "Delaware" "Florida" [11] "Georgia" ``` But would settle for: ``` [1] "ID" "Alabama" "Alaska" "Arizona" "Arkansas" [6] "California" "Colorado" "Connecticut" "Delaware" "Florida" [11] "Georgia" ``` I can get the first part by: ``` unlist(strsplit(x, "[^0-9]*$")) ``` But want the second part. Thank you in advance.