how to write order by and limit query in jpa

java, jpa, persistence

Solution

`limit` is not recognized in JPA. You can instead use the `query.setMaxResults` method:

sm = em.createQuery("select m from MasterScrip m where m.type = :type 
        order by m.totalTradedVolume")
    .setParameter("type", type)
    .setMaxResults(2).getResultList()

Problem

Possible Duplicate: Select top 1 result using JPA i wish to fetch top 10 results based on 'totalTradedVolume' filed of my table 'MasterScrip' when i write the following query: ``` Collection<MasterScrip> sm=null; sm=em.createQuery("select m from MasterScrip m where m.type = :type order by m.totalTradedVolume limit 2").setParameter("type", type).getResultList(); ``` i get the following exception : ``` Caused by: java.lang.IllegalArgumentException: An exception occurred while creating a query in EntityManager: Exception Description: Syntax error parsing the query [select m from MasterScrip m where m.type = :type order by m.totalTradedVolume limit 2], line 1, column 78: unexpected token [limit]. Internal Exception: NoViableAltException(80@[]) ``` something's wrong with my jpa query. can anyone pls correct me?

Original source

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