how to subtract one date to another using php
php
Solution
From how to subtract two dates and times to get difference by VolkerK:
You have to use like this:-
<?php
//$now = new DateTime(); // current date/time
$now = new DateTime("2010-07-28 01:11:50");
$ref = new DateTime("2010-07-30 05:56:40");
$diff = $now->diff($ref);
printf('%d days, %d hours, %d minutes', $diff->d, $diff->h, $diff->i);
prints 2 days, 4 hours, 44 minutes
see http://docs.php.net/datetime.diff
edit: But you could also shift the problem more to the database side, e.g. by storing the expiration date/time in the table and then do a query like ... `WHERE key='7gedufgweufg' AND expires<Now()` Many rdbms have reasonable/good support for date/time arithmetic.
Link Url:- how to subtract two dates and times to get difference
http://www.webpronews.com/calculating-the-difference-between-two-dates-using-php-2005-11
Problem
I want to subtract one date to another using php and display result in the days - hours - min - sec format. How i do this using php . I tried this using time stamp but it does not give proper values. please give suggestion For ex : from date 2012-04-27 19:30:56 to date 2012-04-27 19:37:56 i used this code ``` if(strtotime($history['datetimestamp']) > strtotime($lasttime)) { $totalelapsed1 = (strtotime($history['datetimestamp'])-strtotime($lasttime)); if($totalelapsed1 > 60 ) { $sec = $totalelapsed1%60; $min = round($totalelapsed1/60 , 0); $minute = $min + $minute; $second = $sec + $second; // echo $min. " min " .$sec." sec"; } else { //echo "0 min " . $totalelapsed1." sec"; $minute = 0 + $minute; $second = $totalelapsed1 + $second; } } else { $minute = 0 + $minute; $second = 0 + $second; // echo "0 min 0 sec"; } ```