Why unicode() uses str() on my object only with no encoding given?
encoding, python, unicode
Solution
The behaviour does seem confusing, but intensional. I reproduce here the entirety of the unicode documentation from the Python Built-In Functions documentation (for version 2.5.2, as I write this):
unicode([object[, encoding [, errors]]])
Return the Unicode string version of object using one of the following modes:
If encoding and/or errors are given, unicode() will decode the object which can either be an 8-bit string or a character buffer using the codec for encoding. The encoding parameter is a string giving the name of an encoding; if the encoding is not known, LookupError is raised. Error handling is done according to errors; this specifies the treatment of characters which are invalid in the input encoding. If errors is 'strict' (the default), a ValueError is raised on errors, while a value of 'ignore' causes errors to be silently ignored, and a value of 'replace' causes the official Unicode replacement character, U+FFFD, to be used to replace input characters which cannot be decoded. See also the codecs module.
If no optional parameters are given, unicode() will mimic the behaviour of str() except that it returns Unicode strings instead of 8-bit strings. More precisely, if object is a Unicode string or subclass it will return that Unicode string without any additional decoding applied.
For objects which provide a __unicode__() method, it will call this method without arguments to create a Unicode string. For all other objects, the 8-bit string version or representation is requested and then converted to a Unicode string using the codec for the default encoding in 'strict' mode.
New in version 2.0. Changed in version 2.2: Support for __unicode__() added.
So, when you call `unicode(r, 'utf-8')`, it requires an 8-bit string or a character buffer as the first argument, so it coerces your object using the `__str__()` method, and attempts to decode that using the `utf-8` codec. Without the `utf-8`, the `unicode()` function looks for a for a `__unicode__()` method on your object, and not finding it, calls the `__str__()` method, as you suggested, attempting to use the default codec to convert to unicode.
Problem
I start by creating a string variable with some non-ascii utf-8 encoded data on it: ``` >>> text = 'á' >>> text '\xc3\xa1' >>> text.decode('utf-8') u'\xe1' ``` Using `unicode()` on it raises errors... ``` >>> unicode(text) Traceback (most recent call last): File "<stdin>", line 1, in <module> UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 0: ordinal not in range(128) ``` ...but if I know the encoding I can use it as second parameter: ``` >>> unicode(text, 'utf-8') u'\xe1' >>> unicode(text, 'utf-8') == text.decode('utf-8') True ``` Now if I have a class that returns this text in the `__str__()` method: ``` >>> class ReturnsEncoded(object): ... def __str__(self): ... return text ... >>> r = ReturnsEncoded() >>> str(r) '\xc3\xa1' ``` `unicode(r)` seems to use `str()` on it, since it raises the same error as `unicode(text)` above: ``` >>> unicode(r) Traceback (most recent call last): File "<stdin>", line 1, in <module> UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 0: ordinal not in range(128) ``` Until now everything is as planned! But as no one would ever expect, `unicode(r, 'utf-8')` won't even try: ``` >>> unicode(r, 'utf-8') Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: coercing to Unicode: need string or buffer, ReturnsEncoded found ``` Why? Why this inconsistent behavior? Is it a bug? is it intended? Very awkward.