signed to unsigned casting
c++, signed, types, unsigned
Solution
`-1` in an unsigned representation of the largest possible number unsigned can hold (`UINT_MAX`).
Adding 1 to this wraps over due to the properties of `unsigned`, thus equaling 0.
Problem
look at this code: ``` void main () { int i = -1; unsigned u = 1; cout << u + i; } ``` the addition of the u (unsigned) and i (signed), so i must be converted to the unsigned type, so it should be interpreted ( (2 ^ 32) - 1 ) and the expression should change from: -1 + 1 to ( (2 ^ 32) - 1 ) + 1 but when i run the code it results to 0 why?