python - replace escape character to convert hexa string from 0x to \x

Question

i'm trying to print ascii or extended ascii character. using this code : ``` print '\xff'.decode('latin-1') ``` it will print ascii #255, but now i want to input using decimal number like this : ``` num=255 myhex=hex(num) print myhex.decode('latin-1') ``` It doesn't work coz myhex is '0xff' , so i need to convert into '\xff'. replacing the '0x' with '\x' is giving me error. ``` myhex.replace('0x','\x') ``` will give me error : ValueError: invalid \x escape How to solve the problem? anyone can help ? the goal i want to print char -> ÿ in terminal/console.

Accepted Answer

what you're searching for is

```
chr(255)
```

In python2, that gives you a character with binary value 255. If you print that to a terminal that uses UTF8, it will show up as `?` (or similar) because the terminal doesn't know what to do with it. To convert that to it's unicode codepoint, you can `decode` it:

```
chr(255).decode('latin1')
```

In python3, `chr(255)` already gives you the unicode charcter `'LATIN SMALL LETTER Y WITH DIAERESIS'`.

you could also do the same in python2 using

```
unichr(255)
```

python -> replace escape character to convert hexa string from 0x to \x

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