Fastest way to Remove Duplicate Value from a list<> by lambda

c#, c#-4.0, generic-list, lambda, list

Solution

The easiest way to get a new list would be:

List<long> unique = longs.Distinct().ToList();

Is that good enough for you, or do you need to mutate the existing list? The latter is significantly more long-winded.

Note that `Distinct()` isn't guaranteed to preserve the original order, but in the current implementation it will - and that's the most natural implementation. See my Edulinq blog post about `Distinct()` for more information.

If you don't need it to be a `List<long>`, you could just keep it as:

IEnumerable<long> unique = longs.Distinct();

At this point it will go through the de-duping each time you iterate over `unique` though. Whether that's good or not will depend on your requirements.

Problem

what is fastest way to remove duplicate values from a list. Assume `List<long> longs = new List<long> { 1, 2, 3, 4, 3, 2, 5 };` So I am interesting in use lambda to remove duplicate and returned : `{1, 2, 3, 4, 5}`. What is your suggestion?

Original source