Deploying and running a war file

java, jaxb, jersey, tomcat, war

Solution

The URL of a web app depends on many factors, the app server, configuration files, web.xml, and app server specific configuration.

But in some cases this is a "first thing to try if you don't know" (not an official, but "it works" rule of thumb)

http://hostnameOrIP:8080/WARFILENAMEWITHOUTEXTENSION

- hostnameOrIP: well, just replace with your host name or IP

- replace 8080 with the default port of your app server (9001, 9090, 3000 etc...)

- replace WARFILENAMEWITHOUTEXTENSION with, well, again, just war file name without extension

This is again an unofficial, try-it-first way if you have no other way to tell...

Problem

(Please see the code Code below) I am able to run it on Tomcat in the eclipse environment and it works as it should. I have exported the following to a war file and created a Manifest.MF with: ``` Manifest-Version: 1.0 Main-Class: com.process.Test ``` When the code is ran in Eclipse the response from there server side is output to a console. Now finally my question (Pardon my ignorance, I am fairly new to this): Once the war is deployed on my Tomcat server, how do I send a REST request or run the war and display the server response? What is the equivalent to :http://localhost:8080/rest/xml/list on a live server? Web.xml ``` <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5"> <display-name>com.process.Test</display-name> <servlet> <servlet-name>Jersey REST Service</servlet-name> <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class> <init-param> <param-name>com.sun.jersey.config.property.packages</param-name> <param-value>com.process.Test</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>Jersey REST Service</servlet-name> <url-pattern>/rest/*</url-pattern> </servlet-mapping> </web-app> ``` Client side code: ``` import java.net.URI; import javax.ws.rs.core.MediaType; import javax.ws.rs.core.UriBuilder; import com.sun.jersey.api.client.Client; //import com.sun.jersey.api.client.ClientResponse; import com.sun.jersey.api.client.WebResource; import com.sun.jersey.api.client.config.ClientConfig; import com.sun.jersey.api.client.config.DefaultClientConfig; public class Test { public static void main(String[] args) { //Instead on using Apache Client //used default Jersey client //to send requests ClientConfig config = new DefaultClientConfig(); Client client = Client.create(config); String _package = "api.amebatv.com"; WebResource service = client.resource(getBaseURI(_package)); //runRequest(service,"indexpath"); runRequest(service,"list"); } /* * For testing purposes the base URI is :http://localhost:8080/package name * Will change to domain name for production code */ private static URI getBaseURI(String _package){ return UriBuilder.fromUri( "http://localhost:8080/api.process.com").build(); } private static void runRequest(WebResource service,String path){ String response = service.path("rest/xml/"+path).accept(MediaType.APPLICATION_XML).get(String.class); System.out.println("Post Response :"+response); } } ``` Server Side: ``` @Path("/xml") public class Service { // List of video objects private ArrayList<Video> videolist; //Parser object, parses xml into video objects private Parser parser = new Parser(); /* * Constructor * Parse XML and create video list on call */ public Service(){ parser.createXML(); videolist = parser.getList(); } /************************************************ *GET * Path: /indexpath * list of all only <video> items * @return : ArrayList of Video objects ***********************************************/ @GET @Path("/list") @Produces(MediaType.APPLICATION_XML) public List<Video> getCustomerInXML() { return videolist; } } ```

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