Is it possible to dereference a reference in PHP?

php

Solution

Very interesting question! I may have found a workaround: if you populate the array with object references, with the `&` operator, you can destroy the original object by setting that array value to `NULL`. You have to operate on the array directly, instead of using a variable returned by `array_pop`. After that you can pop the array to free that position (that would then contain a `NULL` value).

This is what I mean (based on Rocket's code):

$a=(object)'a';
$b=array(&$a);
$b[0] = NULL;
// array still contains an element
array_pop($b);
// now array is empty
var_dump($a); // NULL

http://codepad.org/3D7Lphde

Problem

I have an array I'm using as a stack to store a path through a tree. Each element points to a node in the tree and I want to pop the last element off and then set the object referred to by that element to null. Basically: ``` $node = array_pop($path); *$node = null; ``` assuming that PHP had a '*' operator as C-ish languages do. Right now I have the ugly solution of starting at the parent node and remembering which child I took and then setting that to null as in: ``` if($goLeft) { $parent->left = null; } else { $parent->right = null; } ``` I say this is ugly because the array containing the path is created by a public function in my tree class. I'd like to expose the ability to work directly on the nodes in a path through the tree without exposing an implementation detail that addresses an idiosyncrasy (feature?) in PHP. ATM I need to include a boolean in the return value ($goLeft in this case) just so I can workaround an inability to dereference a reference. This is the second time I've encountered this problem, so if anyone knows a way I can do something similar to the first block of code please share! (EDIT) After experimenting with many permutations of &'s and arrays, it turns out that the basic problem was that I had misinterpreted the reason for an error I was getting. I tried ``` $a = ($x > $y) ? &$foo[$bar] : $blah; ``` and got " syntax error, unexpected '&' ". I interpreted this to mean that the problem was using the &-operator on `$foo[$bar]`. It actually turns out that the culprit is the ?-operator, as ``` if($x > $y) { $a = &$foo[$bar]; } else { $a = null; } ``` works perfectly fine. I thus went on a wild goose chase looking for a workaround for a problem that didn't exist. As long as I don't break the chain of &'s, PHP does what I want, which is to operate on the object referred to by a variable (not the variable itself). Example ``` $a1 = new SomeClass; $a2 = &$a1; $a3 = &$a2; $a4 = &$a3; $a4 = 42; // This actually sets $a1 to 42 var_dump($a1); // Emits 42 ``` What messed me up is that I thought objects are passed around by reference anyway (this is wrong), so I didn't think the & was necessary if the expression resolved to an object. I mean: ``` class A { public $b; } class B {} $a = new A; $a->b = new B; $c1 = $a->b; $c2 = &$a->b; $c1 = 42; // Merely assigns 42 to $c1 $c2 = 42; // Assigns 42 to $a->b ``` It turns out that this exact issue is addressed at http://www.php.net/manual/en/language.oop5.references.php. Wish that had sunk in the first time I read it!

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