Scons. Go recursive with Glob

scons

Solution

Sure. You need to write python wrappers to walking through dirs. You can find many recipes on stackoverflow. Here is my simple function which returns list of subdirs in present dir (and ignore hide dirs starting with '.' - dot)

def getSubdirs(abs_path_dir) :  
    lst = [ name for name in os.listdir(abs_path_dir) if os.path.isdir(os.path.join(abs_path_dir, name)) and name[0] != '.' ]
    lst.sort()
    return lst

For example, i've dir modules what containts foo, bar, ice.

corePath = 'abs/path/to/modules'
modules = getSubdirs(corePath)
# modules = [bar, foo, ice]
for module in modules :
  sources += Glob(os.path.join(corePath, module, '*.cpp'))

You can improve getSubdirs function adding recurse and walking deeper to subdirs.

Problem

I using scons for a few days and confused a bit. Why there is no built-in tools for building sources recursively starting from given root? Let me explain: I have such source disposition: ``` src Core folder1 folder2 subfolder2_1 Std folder1 ``` ..and so on. This tree could be rather deeper. Now I build this with such construction: ``` sources = Glob('./builds/Std/*/*.cpp') sources = sources + Glob('./builds/Std/*.cpp') sources = sources + Glob('./builds/Std/*/*/*.cpp') sources = sources + Glob('./builds/Std/*/*/*/*.cpp') ``` and this looks not so perfect as at can be. Of cause, I can write some python code, but is there more suitable ways of doing this?

Original source