Wrong output for integer comparison values
comparison, int, integer, java
Solution
The last line corresponds to:
compareInt(100, 100);
Since `compareInt()` takes two `Integer` objects, the two parameters get auto-boxed. During that process, instances of `Integer(n)` for small values of `n` get interned. In other words, `compareInt()` receives two references to the same `Integer(100)` object. This is what's causing the last comparison to evaluate to `true`.
See Using == operator in Java to compare wrapper objects
The bottom line is to not use the `==` operator for directly comparing `Integer` objects. For further discussion, see https://stackoverflow.com/a/1515811/367273
Problem
I have the following code. ``` public static void doIntCompareProcess() { int a = 100; int b = 100; Integer c = 200; Integer d = 200; int f = 20000; int e = 20000; System.out.println(c == d); compareInt(e, f); compareInt(a, b); } public static void compareInt(Integer v1, Integer v2) { System.out.println(v1 == v2); } ``` That gives me this output: ``` false false true ``` Where the currect output should be: ``` false false false ``` Why am I getting the wrong output for the code?