How can I print the same variable into a string several times?

c, printf

Solution

Yes, you can use `%1$d` everytime. The `1$` references the second argument, you could obviously do it with other arguments, too.

Demo: http://codepad.org/xVmdJkpN

Note that the position specifier is a POSIX extension - so it might not work with every single compiler. If you need it to work e.g. with the Visual C++ compiler, consider using the ugly way of repeating the argument or do not use a printf-style function at all. Another option would be using a POSIX-compatible sprintf implementation or using multiple calls to append one number everytime in a loop (in case the format string is built dynamically which would prevent you from specifying the correct number of arguments).

On a side-note, `sprintf` should be avoided. Use `snprintf(buf2, sizeof(buf2), ....)` instead. Of course this requires `buf2` to have a static size known at compile-time - but if you allocate it manually you can simply use the variable containing the length instead of `sizeof(buf2)`.

Problem

I have a format string like this: ``` buf[] = "A%d,B%d,C%d,D%d,F%d,G%d,H%d,I%d,J%d"; ``` and I want to insert the same integer for each `%d` so I use: ``` int val = 6; sprintf(buf2, buf, val,val,val,val,val,val,val,val,val); ``` Can I use `sprintf` in a way that only requires me to write `val` once, and `sprintf` will use it for each `%d`?

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