get current directory of symlink'd php script and not actual php script
directory, php, symlink
Solution
For Web Server requests
dirname($_SERVER['SCRIPT_FILENAME']) will give you what you need.
Failing that $_SERVER['PHP_SELF'] or even REQUEST_URI may have what you need, depending on your server configuration.
For CLI (command Line)
this won't work in cli (command line) scripts as $_SERVER is added by the web server.
Fortunately it's a lot easier with cli scripts (as there is no web server to mess about with things).
All you need is to read the command line that started the script: http://php.net/manual/en/reserved.variables.argv.php. The first argument $argv[0] is always the name that was used to run the script.
Problem
I have a script that is symlinked from one folder to another ``` /var/www/default/index.php ``` which is symlinked to ``` /var/www/mysite/index.php ``` However when i call DIR from mysite the path resolves to the origial path under default. How do i make it return the mysite path (the symlinked folder, not the actual folder)