Replace BOOST_FOREACH with "pure" C++11 alternative?

boost, boost-foreach, c++, c++11

Solution

for (auto & i : map)
{
    std::tie(k,v) = i;
    // your code here
}

Problem

Is it possible to replace the `BOOST_FOREACH` in this example with a "pure" C++11 equivalent? ``` #include <map> #include <functional> #include <boost/foreach.hpp> #include <iostream> int main() { std::map<int, std::string> map = {std::make_pair(1,"one"), std::make_pair(2,"two")}; int k; std::string v; BOOST_FOREACH(std::tie(k, v), map) { std::cout << "k=" << k << " - " << v << std::endl; } } ``` The key feature being keeping the key/value pair in the references to `k` and `v`. I tried: ``` for(std::tie(k,v) : map) { std::cout << "k=" << k << " - " << v << std::endl; } ``` and ``` auto i = std::tie(k,v); for(i : map) { std::cout << "k=" << k << " - " << v << std::endl; } ``` But none of the ranged based for loop ideas seemed to work. Presumably the ranged based for loop is required to have a declaration before the `:`, since even: ``` std::vector<int> test; int i; for (i : test); ``` Isn't valid. The closest equivalent I can find is: ``` for (auto it = map.begin(); it!=map.end() && (std::tie(k,v)=*it,1); ++it) { std::cout << "k=" << k << " - " << v << std::endl; } ``` which isn't quite as succinct as the `BOOST_FOREACH` version! Is there a way to express the same thing succinctly without boost in C++11?

Original source